QuestionSBA
QuestionChoice
Yes, this is the correct answer. 1.5 x 10^-7 is converted to µmol by multiplying by 10^6. So 1.5 x 10^-7 x 10^6 = 0.15 µmol. If there is 0.15 µmol produced per 0.1 ml of serum. We can then calculate how much is produced in 1 litre. 0.15 x 10^4 = 1500 µmol/L. And since we know how much phosphocreatine was made in one minute, the activity would be 1500 µmol/L/min. Note that 1 unit is the amount of enzyme
that produces 1 µmol of product per minute.
10007970
a
1500 µmol/L/min
QuestionChoice
No, this is not the correct answer.
10007971
b
1500 nmol/L/min
QuestionChoice
No, this is not the correct answer.
10007973
d
0.3 mol/L/min
QuestionChoice
No, this is not the correct answer.
10007972
c
1.5 µmol/L/min
QuestionChoice
No, this is not the correct answer.
10007974
e
0.15 mmol/L/min
Concept
Chapter
2693
3713
Myocardial infarction and Acute Coronary Syndrome (ACS)
Topic
134
Cardiology
14141
A 54-year-old man presents to A&E  with central crushing chest pain referring to the jaw and arm. An ECG shows ST-segment elevation in leads I, avL, V5 & V6.

A diagnosis of a lateral STEMI is made. Creatine Kinase (CK) can be used to confirm this diagnosis.

The reaction catalysed by creatine kinase is shown below:

**Creatine + ATP ⇌ Phosphocreatine + ATP**

0.1 ml of serum was assayed and was shown to produce 1.5 x 10^-7 moles of phosphocreatine per minute.

What is the activity of creatine kinase (CK) in units per litre of serum?
a